One gas bleaches the colour of flowers by reduction while the other by oxidation. The two gases respectively are:

  • A
    $CO$ and $Cl_2$
  • B
    $H_2S$ and $Br_2$
  • C
    $NH_3$ and $SO_3$
  • D
    $SO_2$ and $Cl_2$

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What is the reason for the bleaching action of chlorine?

Which among the following compounds is $NOT$ a colourless gas?

What are the products formed when fluorine reacts with dilute $NaOH$ and concentrated $NaOH$,respectively?

Which of the following reactions are correct with respect to the formation of products?
$I$. $2 NaOH + SO_2 \longrightarrow Na_2SO_3 + H_2O$
$II$. $XeF_4 + O_2F_2 \stackrel{143 K}{\longrightarrow} XeF_6 + O_2$
$III$. $PCl_5 + 4 H_2O \longrightarrow H_3PO_4 + 5 HCl$
$IV$. $2 NaNO_2 + 2 HCl \longrightarrow 2 NaCl + NO + NO_2 + H_2O$

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